How heavy is a 3 inch steel ball?
Views: 145 Update Date:Oct 14 , 2024
To determine the weight of a 3-inch steel ball, we need to follow these steps:
1. Calculate the volume of the ball
2. Determine the density of steel
3. Multiply the volume by the density
- V = (4/3) * π * (1.5 in)³
- V ≈ 14.137 cubic inches
- Weight = 14.137 in³ * 0.284 lbs/in³
- Weight ≈ 4.015 pounds
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1. Calculate the volume of the ball
2. Determine the density of steel
3. Multiply the volume by the density
Let's go through this process:
1. Volume of a sphere: V = (4/3) * π * r³
- Diameter is 3 inches, so radius (r) is 1.5 inches- V = (4/3) * π * (1.5 in)³
- V ≈ 14.137 cubic inches
2. Density of steel:
- Steel density can vary slightly depending on the specific alloy, but a common average is about 0.284 pounds per cubic inch3. Weight calculation:
- Weight = Volume * Density- Weight = 14.137 in³ * 0.284 lbs/in³
- Weight ≈ 4.015 pounds
Therefore, a 3-inch steel ball would weigh approximately 4 pounds (or about 1.82 kg).